Optimal. Leaf size=145 \[ \frac{4 e (d+e x)}{5 d \left (d^2-e^2 x^2\right )^{5/2}}-\frac{\sqrt{d^2-e^2 x^2}}{d^5 x}+\frac{e (15 d+19 e x)}{5 d^5 \sqrt{d^2-e^2 x^2}}+\frac{e (5 d+7 e x)}{5 d^3 \left (d^2-e^2 x^2\right )^{3/2}}-\frac{3 e \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right )}{d^5} \]
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Rubi [A] time = 0.287314, antiderivative size = 145, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.185, Rules used = {1805, 807, 266, 63, 208} \[ \frac{4 e (d+e x)}{5 d \left (d^2-e^2 x^2\right )^{5/2}}-\frac{\sqrt{d^2-e^2 x^2}}{d^5 x}+\frac{e (15 d+19 e x)}{5 d^5 \sqrt{d^2-e^2 x^2}}+\frac{e (5 d+7 e x)}{5 d^3 \left (d^2-e^2 x^2\right )^{3/2}}-\frac{3 e \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right )}{d^5} \]
Antiderivative was successfully verified.
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Rule 1805
Rule 807
Rule 266
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{(d+e x)^3}{x^2 \left (d^2-e^2 x^2\right )^{7/2}} \, dx &=\frac{4 e (d+e x)}{5 d \left (d^2-e^2 x^2\right )^{5/2}}-\frac{\int \frac{-5 d^3-15 d^2 e x-16 d e^2 x^2}{x^2 \left (d^2-e^2 x^2\right )^{5/2}} \, dx}{5 d^2}\\ &=\frac{4 e (d+e x)}{5 d \left (d^2-e^2 x^2\right )^{5/2}}+\frac{e (5 d+7 e x)}{5 d^3 \left (d^2-e^2 x^2\right )^{3/2}}+\frac{\int \frac{15 d^3+45 d^2 e x+42 d e^2 x^2}{x^2 \left (d^2-e^2 x^2\right )^{3/2}} \, dx}{15 d^4}\\ &=\frac{4 e (d+e x)}{5 d \left (d^2-e^2 x^2\right )^{5/2}}+\frac{e (5 d+7 e x)}{5 d^3 \left (d^2-e^2 x^2\right )^{3/2}}+\frac{e (15 d+19 e x)}{5 d^5 \sqrt{d^2-e^2 x^2}}-\frac{\int \frac{-15 d^3-45 d^2 e x}{x^2 \sqrt{d^2-e^2 x^2}} \, dx}{15 d^6}\\ &=\frac{4 e (d+e x)}{5 d \left (d^2-e^2 x^2\right )^{5/2}}+\frac{e (5 d+7 e x)}{5 d^3 \left (d^2-e^2 x^2\right )^{3/2}}+\frac{e (15 d+19 e x)}{5 d^5 \sqrt{d^2-e^2 x^2}}-\frac{\sqrt{d^2-e^2 x^2}}{d^5 x}+\frac{(3 e) \int \frac{1}{x \sqrt{d^2-e^2 x^2}} \, dx}{d^4}\\ &=\frac{4 e (d+e x)}{5 d \left (d^2-e^2 x^2\right )^{5/2}}+\frac{e (5 d+7 e x)}{5 d^3 \left (d^2-e^2 x^2\right )^{3/2}}+\frac{e (15 d+19 e x)}{5 d^5 \sqrt{d^2-e^2 x^2}}-\frac{\sqrt{d^2-e^2 x^2}}{d^5 x}+\frac{(3 e) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{d^2-e^2 x}} \, dx,x,x^2\right )}{2 d^4}\\ &=\frac{4 e (d+e x)}{5 d \left (d^2-e^2 x^2\right )^{5/2}}+\frac{e (5 d+7 e x)}{5 d^3 \left (d^2-e^2 x^2\right )^{3/2}}+\frac{e (15 d+19 e x)}{5 d^5 \sqrt{d^2-e^2 x^2}}-\frac{\sqrt{d^2-e^2 x^2}}{d^5 x}-\frac{3 \operatorname{Subst}\left (\int \frac{1}{\frac{d^2}{e^2}-\frac{x^2}{e^2}} \, dx,x,\sqrt{d^2-e^2 x^2}\right )}{d^4 e}\\ &=\frac{4 e (d+e x)}{5 d \left (d^2-e^2 x^2\right )^{5/2}}+\frac{e (5 d+7 e x)}{5 d^3 \left (d^2-e^2 x^2\right )^{3/2}}+\frac{e (15 d+19 e x)}{5 d^5 \sqrt{d^2-e^2 x^2}}-\frac{\sqrt{d^2-e^2 x^2}}{d^5 x}-\frac{3 e \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right )}{d^5}\\ \end{align*}
Mathematica [C] time = 0.0602409, size = 96, normalized size = 0.66 \[ \frac{3 d^5 e x \, _2F_1\left (-\frac{5}{2},1;-\frac{3}{2};1-\frac{e^2 x^2}{d^2}\right )+45 d^4 e^2 x^2-60 d^2 e^4 x^4+d^5 e x-5 d^6+24 e^6 x^6}{5 d^5 x \left (d^2-e^2 x^2\right )^{5/2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.064, size = 190, normalized size = 1.3 \begin{align*}{\frac{4\,e}{5} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{-{\frac{5}{2}}}}+{\frac{9\,{e}^{2}x}{5\,d} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{-{\frac{5}{2}}}}+{\frac{12\,{e}^{2}x}{5\,{d}^{3}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{-{\frac{3}{2}}}}+{\frac{24\,{e}^{2}x}{5\,{d}^{5}}{\frac{1}{\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}}}+{\frac{e}{{d}^{2}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{-{\frac{3}{2}}}}+3\,{\frac{e}{{d}^{4}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}}-3\,{\frac{e}{{d}^{4}\sqrt{{d}^{2}}}\ln \left ({\frac{2\,{d}^{2}+2\,\sqrt{{d}^{2}}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}{x}} \right ) }-{\frac{d}{x} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{-{\frac{5}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.69005, size = 374, normalized size = 2.58 \begin{align*} \frac{24 \, e^{4} x^{4} - 72 \, d e^{3} x^{3} + 72 \, d^{2} e^{2} x^{2} - 24 \, d^{3} e x + 15 \,{\left (e^{4} x^{4} - 3 \, d e^{3} x^{3} + 3 \, d^{2} e^{2} x^{2} - d^{3} e x\right )} \log \left (-\frac{d - \sqrt{-e^{2} x^{2} + d^{2}}}{x}\right ) -{\left (24 \, e^{3} x^{3} - 57 \, d e^{2} x^{2} + 39 \, d^{2} e x - 5 \, d^{3}\right )} \sqrt{-e^{2} x^{2} + d^{2}}}{5 \,{\left (d^{5} e^{3} x^{4} - 3 \, d^{6} e^{2} x^{3} + 3 \, d^{7} e x^{2} - d^{8} x\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (d + e x\right )^{3}}{x^{2} \left (- \left (- d + e x\right ) \left (d + e x\right )\right )^{\frac{7}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.22195, size = 250, normalized size = 1.72 \begin{align*} -\frac{\sqrt{-x^{2} e^{2} + d^{2}}{\left ({\left ({\left ({\left (x{\left (\frac{19 \, x e^{6}}{d^{5}} + \frac{15 \, e^{5}}{d^{4}}\right )} - \frac{45 \, e^{4}}{d^{3}}\right )} x - \frac{35 \, e^{3}}{d^{2}}\right )} x + \frac{30 \, e^{2}}{d}\right )} x + 24 \, e\right )}}{5 \,{\left (x^{2} e^{2} - d^{2}\right )}^{3}} - \frac{3 \, e \log \left (\frac{{\left | -2 \, d e - 2 \, \sqrt{-x^{2} e^{2} + d^{2}} e \right |} e^{\left (-2\right )}}{2 \,{\left | x \right |}}\right )}{d^{5}} + \frac{x e^{3}}{2 \,{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )} d^{5}} - \frac{{\left (d e + \sqrt{-x^{2} e^{2} + d^{2}} e\right )} e^{\left (-1\right )}}{2 \, d^{5} x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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